A small object slides down with initial velocity equal to zero from the top of a smooth hill of height H. The other end of the hill is horizontal and…

Question

A small object slides down with initial velocity equal to zero from the top of a smooth hill of height $H$ . The other end of the hill is horizontal and is at height $\frac{H}{2}$ as shown in the figure. The horizontal distance covered by the object from the end of the hill to the ground is

MARKS Content Team · Accepted Answer

Correct answer: (B) H. Since the platform is smooth, the speed of the object when it comes down by h=H/2 will be, v=√2gh=√2gH2=√gH The time taken to fall the height h=H/2 t=√2hg=√Hg Horizontal displacement in this time will be, x=vt=√gH×√Hg=H

A small object slides down with initial velocity equal to zero from the top of a smooth hill of height $H$ . The other end of the hill is horizontal and is at height $\frac{H}{2}$ as shown in the figure. The horizontal distance covered by the object from the end of the hill to the ground is

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Relevant Questions

A small object slides down with initial velocity equal to zero from the top of a smooth hill of height H. The other end of the hill is horizontal and is at height H2 as shown in the figure. The horizontal distance covered by the object from the end of the hill to the ground is

Solution

Relevant Questions

A small object slides down with initial velocity equal to zero from the top of a smooth hill of height $H$ . The other end of the hill is horizontal and is at height $\frac{H}{2}$ as shown in the figure. The horizontal distance covered by the object from the end of the hill to the ground is