A small, metal wire loop is dragged across the gap between the poles of a magnet in $\text{0.4} \mathrm{s}$. If the change in magnetic flux for the wire is $8\times {10}^{-4} \mathrm{Wb}$, then the emf induced in the wire is

• A

  $8\times {10}^{-3} \mathrm{V}$
• B

  $6\times {10}^{-3} \mathrm{V}$
• C

  $4\times {10}^{-3}\mathrm{ }\mathrm{V}$
• Correct answer
  D

  $2\times {10}^{-3} \mathrm{V}$

Hence, the correct answer is option: 'D'.