Q129 / 150 · MHT CET 2019 (Shift 2) · Physics

A simple harmonic progressive wave is represented as y = 0.03 sinπ2t-0.01xm . At a given instant of time, the phase difference between two particles 25 m apart is

  • A
    πrad
  • B
    π2rad
  • Correct answer
    C
    π4rad
  • D
    π8rad

Solution

The given equation of SHM wave is
y=0.03sinπ2t-0.01xm
= 0.03sin⁡2πt-0.01πxm
Comparing it with general equation, we get
y=asin⁡ωt-kx
Where, k=2πλ⇒λ=200m
The phase difference between two particles is given by
Δϕ=kx=2πλ×x … (i)
Here, x = 25 m
Substituting the values of x an λ in Eq. (i), we get
Δϕ=2π200×25=π4rad

Hence, the correct answer is option: 'C'.

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