A short bar magnet is placed in a uniform magnetic field of 2 T such that the axis of the magnet makes an angle of $45^{\circ}$ with the direction of the magnetic field. If the torque acting on the magnet is $0.36 \sqrt{2} \mathrm{Nm}$, then the moment of the magnet is

• A

  $0.54 \mathrm{~J} \mathrm{~T}^{-1}$
• B

  $0.18 \mathrm{~J} \mathrm{~T}^{-1}$
• C

  $0.72 \mathrm{~J} \mathrm{~T}^{-1}$
• Correct answer
  D

  $0.36 \mathrm{~J} \mathrm{~T}^{-1}$

Hence, the correct answer is option: 'D'.