Q29 / 225 · JEE Main 2005 · Chemistry

A schematic plot of ln $\mathrm{K}_{\text {eq }}$ versus inverse of temperature for a reaction is shown below Figure
The reaction must be

  • Correct answer
    A
    exothermic
  • B
    endothermic
  • C
    one with negligible enthalpy change
  • D
    highly spontaneous at ordinary temperature

Solution

$\mathrm{K}_{\mathrm{eq}}=\mathrm{A} \mathrm{e}^{-\frac{\Delta \mathrm{H}}{\mathrm{RT}}}$

Hence, the correct answer is option: 'A'.

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