Q121 / 150 · MHT CET 2025 (26 Apr Shift 1) · Physics
A rigid body rotates about a fixed axis with variable angular velocity ($\propto-\beta \mathrm{t}$) at time t, where $\propto$ and $\beta$ are constants. The angle through which it rotates before it comes to rest is
- A$\frac{\propto}{\beta}$
- B$\frac{\propto^2}{\beta}$
- Correct answerC$\frac{\propto^2}{2 \beta}$
- D$\frac{\propto}{2 \beta}$
Solution
The angular velocity is $\omega = \alpha - \beta t$. The body reaches rest when $\omega = 0$, giving $\alpha - \beta t_f = 0$ and $t_f = \frac{\alpha}{\beta}$.
The total rotation angle is the integral of angular velocity over time:
$\theta = \int_0^{\alpha/\beta} (\alpha - \beta t) \, dt = \left[ \alpha t - \frac{\beta t^2}{2} \right]_0^{\alpha/\beta}$
Evaluating at the limits:
$\theta = \left( \alpha \cdot \frac{\alpha}{\beta} - \frac{\beta}{2} \cdot \frac{\alpha^2}{\beta^2} \right) - 0 = \frac{\alpha^2}{\beta} - \frac{\alpha^2}{2\beta} = \frac{\alpha^2}{2\beta}$
Final answer: $\boxed{\text{C}}$
Hence, the correct answer is option: 'C'.