Q113 / 180 · NEET 2026 (Cancelled) · Physics
A resistor is connected to a battery of $12$ V emf and internal resistance $2\ \Omega$. If the current in the circuit is $0.6$ A, the terminal voltage of the battery is :
- A$10$ V
- B$1.2$ V
- C$12$ V
- Correct answerD$10.8$ V
Solution
The terminal voltage $V$ of a battery discharging in a circuit is given by the relation:
$V = E - Ir$
Substituting the given values $E = 12$ V, $r = 2\ \Omega$, and $I = 0.6$ A:
$V = 12 - (0.6 \times 2)$
$V = 12 - 1.2$
$V = 10.8$ V
Answer: $10.8$ V
$V = E - Ir$
Substituting the given values $E = 12$ V, $r = 2\ \Omega$, and $I = 0.6$ A:
$V = 12 - (0.6 \times 2)$
$V = 12 - 1.2$
$V = 10.8$ V
Answer: $10.8$ V
Hence, the correct answer is option: 'D'.