Q118 / 125 · BITSAT 2010 · Physics
A resistance $\mathrm{R}$ and inductance $\mathrm{L}$ and a capacitor $\mathrm{C}$ all are connected in series with an AC supply. The resistance of $\mathrm{R}$ is 16 ohm and for a given frequency, the inductive reactance of $L$ is 24 ohm and capacitive reactance of $\mathrm{C}$ is $12 \mathrm{ohm} .$ If the current in the circuit is 5 amp., find the potential difference across $\mathrm{R}, \mathrm{L}$ and $\mathrm{C}$.
- A30,20,50 volt
- B40,100,60 volt
- C70,110,60 volt
- Correct answerD80,120,60 volt
Solution
$\mathrm{V}_{\mathrm{R}}=\mathrm{i} \mathrm{R}=5 \times 16=80 \mathrm{Volt}$
$$
\begin{array}{l}
\mathrm{V}_{\mathrm{L}}=\mathrm{i} \times(\omega \mathrm{L})=5 \times 24=120 \mathrm{Volt} \\
\mathrm{V}_{\mathrm{C}}=\mathrm{i} \times(\mathrm{l} / \omega \mathrm{C})=5 \times 12=60 \mathrm{Volt}
\end{array}
$$
Hence, the correct answer is option: 'D'.