A real valued function $f: A \rightarrow B$ defined by $f(x)=\frac{4-x^2}{4+x^2} \forall x \in A$ is a bijection. If $-4 \in A$ then $A \cap B=$

• A

  $(-1,1]$
• B

  $[0,1]$
• C

  $[0, \infty)$
• Correct answer
  D

  $(-1,0]$

Hence, the correct answer is option: 'D'.