Q125 / 150 · MHT CET 2020 (16 Oct Shift 2) · Physics

A ray of light travelling through glass of refractive index $\sqrt{2}$, is incident on glass - air boundary at an angle of incidence $45^{\circ}$. If refractive index of air is 1 , then the angle of refraction will be $\left[\sin 45^{\circ}=\frac{1}{\sqrt{2}}, \quad \sin 90^{\circ}=1\right]$

  • A
    $30^{\circ}$
  • Correct answer
    B
    $90^{\circ}$
  • C
    $60^{\circ}$
  • D
    $45^{\circ}$

Solution

(C) $\mu=\sqrt{2} \mathrm{i}=45^{\circ}$ $\mu_{i} \sin i=\mu_{r} \sin r$ $\Rightarrow \sqrt{2} \sin 45^{\circ}=\sin \mathrm{r}$ $\therefore \quad \mathrm{r}=90^{\circ}$

Hence, the correct answer is option: 'B'.

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