A random variable $X$ has the following probability distribution:
$\begin{array}{c}\begin{array}{ccc}X:& 1& \begin{array}{ccc}2& 3& \begin{array}{cc}4& 5\end{array}\end{array}\end{array}\\ P\left(X\right): \begin{array}{cc}{k}^2& \begin{array}{ccc}2k& k& \begin{array}{cc}2k& 5k^2\end{array}\end{array}\end{array}\end{array}$
Then, $P\left(X>2\right)$ is equal to:

• A

  $\frac{7}{12}$
• B

  $\frac{1}{36}$
• C

  $\frac{1}{6}$
• Correct answer
  D

  $\frac{23}{36}$

Hence, the correct answer is option: 'D'.