Q44 / 108 · NTA Abhyas (JEE Main) 2020 · Mathematics · Probability

A random variable X follows binomial probability distribution with probability P(X),  with mean as 2, probability of success as p and probability of failure as q such that p+q=1. If ΣX2P(X)=285, then the probability of exactly 2 success is

  • A
    3×214510
  • Correct answer
    B
    32×21659
  • C
    3×2510
  • D
    45×259

Solution

Given, x¯=np=2 mean
Variance =npq=ΣX2P(X)-x¯2
npq=285-4⇒npq=85
2×q=85⇒q=45,p=15,n=10
Probability of exactly 2 success is 10C2152458=32×21659

Hence, the correct answer is option: 'B'.

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