Q61 / 150 · MHT CET 2022 (07 Aug Shift 1) · Mathematics

A random variable $X$ has the following probability distribution Figure Then $P\left(X^3 2\right)=$

  • Correct answer
    A
    $\frac{45}{49}$
  • B
    $\frac{15}{49}$
  • C
    $\frac{1}{49}$
  • D
    $\frac{40}{49}$

Solution

$\begin{aligned} & \sum P(x)=1 \\ & \Rightarrow 49 k=1\end{aligned}$ Now, $P\left(x^3 2\right)=1-P(X<2)$ $\begin{aligned} & =1-\{P(X=0)+P(x=1)\} \\ & =1-\left\{\frac{1}{49}+\frac{3}{49}\right\} \\ & =\frac{45}{49}\end{aligned}$

Hence, the correct answer is option: 'A'.

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