Q35 / 104 · NTA Abhyas (JEE Main) 2020 · Physics · Atomic Physics

A radioactive sample at some instant has a disintegration rate of 5000 disintegrations per minute. After 5 minutes, the rate becomes 1250 disintegrations per minute. Then, the decay constant (per minute) is

  • Correct answer
    A
    0.4  ln  2
  • B
    0.2  ln  2
  • C
    0.1  ln  2
  • D
    0.8  ln  2

Solution

A A 0 = 1 2 5 0 5 0 0 0 = 1 4 = 1 2 t T

⇒ T = t 2 = 5 2

λ=ln2T=25ln2

   =0.4 ln2

Hence, the correct answer is option: 'A'.

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