Q90 / 90 · KVPY 2012 (SB/SX) · Physics

A radioactive nucleus A has a single decay mode with half life $\tau_{\mathrm{A}}$. Another radioactive nucleus $\mathrm{B}$ has two decay modes 1 and 2. If decay mode 2 were absent, the half life of $\mathrm{B}$ would have been $\tau_{\mathrm{A}} / 2$. If decay mode 1 were absent, the half life of $\mathrm{B}$ would have been $3 \tau_{\mathrm{A}}$, then the ratio $\tau_{\mathrm{B}} / \tau_{\mathrm{A}}$ is-

  • Correct answer
    A
    $3 / 7$
  • B
    $7 / 2$
  • C
    $7 / 3$
  • D
    1

Solution

$\begin{array}{l} \tau_{\mathrm{B}}=\frac{\tau_{\mathrm{A} / 2} \cdot 3 \tau_{\mathrm{A}}}{\tau_{\mathrm{A} / 2}+3 \tau_{\mathrm{A}}} \\ \frac{\tau_{\mathrm{B}}}{\tau_{\mathrm{A}}}=\frac{3}{7} \end{array}$

Hence, the correct answer is option: 'A'.

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