Q90 / 90 · KVPY 2012 (SB/SX) · Physics
A radioactive nucleus A has a single decay mode with half life $\tau_{\mathrm{A}}$. Another radioactive nucleus $\mathrm{B}$ has two decay modes 1 and 2. If decay mode 2 were absent, the half life of $\mathrm{B}$ would have been $\tau_{\mathrm{A}} / 2$. If decay mode 1 were absent, the half life of $\mathrm{B}$ would have been $3 \tau_{\mathrm{A}}$, then the ratio $\tau_{\mathrm{B}} / \tau_{\mathrm{A}}$ is-
- Correct answerA$3 / 7$
- B$7 / 2$
- C$7 / 3$
- D1
Solution
$\begin{array}{l}
\tau_{\mathrm{B}}=\frac{\tau_{\mathrm{A} / 2} \cdot 3 \tau_{\mathrm{A}}}{\tau_{\mathrm{A} / 2}+3 \tau_{\mathrm{A}}} \\
\frac{\tau_{\mathrm{B}}}{\tau_{\mathrm{A}}}=\frac{3}{7}
\end{array}$
Hence, the correct answer is option: 'A'.