Q33 / 150 · MHT CET 2008 · Chemistry
A radioactive isotope having $t_{1 / 2}=3$ days was read after 12 days. If $3 g$ of isotope is contained in container, the initial weight of isotope was
- A$12 \mathrm{~g}$
- B$24 \mathrm{~g}$
- C$36 \mathrm{~g}$
- Correct answerD$48 \mathrm{~g}$
Solution
$\begin{aligned} T &=n \times t_{1 / 2} \\ 12 &=n \times 3 \\ n &=4 \\ N &=N_{0} \times\left(\frac{1}{2}\right)^{n} \\ 3 &=N_{0} \times\left(\frac{1}{2}\right)^{4} \\ 3 &=N_{0} \times \frac{1}{16} \\ N_{0} &=16 \times 3=48 \mathrm{~g} \end{aligned}$
Hence, the correct answer is option: 'D'.