Q61 / 90 · JEE Main 2023 (01 Feb Shift 1) · Physics

A proton moving with one tenth of velocity of light has a certain de Broglie wavelength of λ. An alpha particle having certain kinetic energy has the same de-Brogle wavelength λ. The ratio of kinetic energy of proton and that of alpha particle is :

  • A
    2 : 1
  • Correct answer
    B
    4 : 1
  • C
    1 : 2
  • D
    1 : 4

Solution

As we know, de Broglie wavelength is given by,

λ=hp

Now kinetic energy can be written as,

K=12mv2=p22m=h22mλ2

Therefore,

K∝1m

Hence, required ratio

KpKα=mαmp=4⇒mα:mp=4:1

Hence, the correct answer is option: 'B'.

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