A proton accelerated by a potential difference $500\mathrm{kV}$ flies through a uniform transverse magnetic field $0.1 \mathrm{T}$. The field is spread on a region of $1.0 \mathrm{cm}$ thickness. The angle through which the proton gets deviated from its original direction is (Proton mass $=1.6\times {10}^{-27} \mathrm{kg}$ and charge of proton$=1.6\times {10}^{-19}\mathrm{C}$ )

• Correct answer
  A

  $0.01\mathrm{rad}$
• B

  $0.1\mathrm{rad}$
• C

  $0.05\mathrm{rad}$
• D

  $0.08\mathrm{rad}$

Hence, the correct answer is option: 'A'.