A projectile is projected from the ground by making an angle of 60° with the horizontal. After 1 s projectile makes an angle of 30° with the…

Question

A projectile is projected from the ground by making an angle of 60° with the horizontal. After 1 s projectile makes an angle of 30° with the horizontal. The maximum height attained by the projectile is (Take g=10 m s^(-2))

MARKS Content Team · Accepted Answer

Correct answer: (B) 45/4 m. tan 30°=(v_0sin 60°-gt)/(v_0cos 60°)⇒(1√3=v_0√32-g×tV_02 ⇒ v_0 2 = 3v_0 2 - gt √3 ⇒ v_0 = gt √3 = g √3 . ∴H_max=v0)/(2sin^2θ2g=300×3/420=454)m

A projectile is projected from the ground by making an angle of $60 °$ with the horizontal. After $1 s$ projectile makes an angle of $30 °$ with the horizontal. The maximum height attained by the projectile is (Take $g = 10 m s^{- 2}$ )

Solution

More Motion In Two Dimensions Questions

A projectile is projected from the ground by making an angle of 60° with the horizontal. After 1 s projectile makes an angle of 30° with the horizontal. The maximum height attained by the projectile is (Take g=10 m s-2)

Solution

More Motion In Two Dimensions Questions

A projectile is projected from the ground by making an angle of $60 °$ with the horizontal. After $1 s$ projectile makes an angle of $30 °$ with the horizontal. The maximum height attained by the projectile is (Take $g = 10 m s^{- 2}$ )