A projectile is launched with an initial speed of 40 m s^(-1) at an angle 30° above the ground. The projectile lands on a hillside 2.0 s later. The…

Question

A projectile is launched with an initial speed of 40 m s^(-1) at an angle 30° above the ground. The projectile lands on a hillside 2.0 s later. The net displacement from where the projectile was launched to where it hits the target is (Take g=10 m s^(-2))

MARKS Content Team · Accepted Answer

Correct answer: (D) 20√13 m. Horizontal displacement covered, x=40cos30°×2=40√3 m Vertical displacement covered, y=40sin30°×2+1/2-10×2^2=40-20=20 m Hence, required displacement will be, √(x^2+y^2)=20√13 m

A projectile is launched with an initial speed of $40 m s^{- 1}$ at an angle $30 °$ above the ground. The projectile lands on a hillside $2.0 s$ later. The net displacement from where the projectile was launched to where it hits the target is (Take $g = 10 m s^{- 2}$ )

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Relevant Questions

A projectile is launched with an initial speed of 40 m s-1 at an angle 30° above the ground. The projectile lands on a hillside 2.0 s later. The net displacement from where the projectile was launched to where it hits the target is (Take g=10 m s-2)

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Relevant Questions

A projectile is launched with an initial speed of $40 m s^{- 1}$ at an angle $30 °$ above the ground. The projectile lands on a hillside $2.0 s$ later. The net displacement from where the projectile was launched to where it hits the target is (Take $g = 10 m s^{- 2}$ )