Q111 / 120 · VITEEE 2011 · Physics

A potentiometer is connected across A and B and a balance is obtained at $64.0 \mathrm{~cm}$. When potentiometer lead to $\mathrm{B}$ is moved to $\mathrm{C}$, a balance is found at $8.0 \mathrm{~cm}$. If the potentometer is now connected across B and C, a balance will be found at Figure

  • A
    $8.0 \mathrm{~cm}$
  • Correct answer
    B
    $56.0 \mathrm{~cm}$
  • C
    $64.0 \mathrm{~cm}$
  • D
    $72.0 \mathrm{~cm}$

Solution

Here, $\mathrm{E}_{1} \propto 64$ $\mathrm{E}_{1}-\mathrm{E}_{2} \propto 8$ $\mathrm{E}_{2} \propto l$ $\therefore \quad 64-l=8$ or $l=64-8=56 \mathrm{~cm}$

Hence, the correct answer is option: 'B'.

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