Q85 / 90 · JEE Main 2022 (29 Jun Shift 2) · Physics

A potential barrier of 0.4 V exists across a p-n junction. An electron enters the junction from the n-side with a speed of 6.0×105 m s-1. The speed with which electron enters the p side will be x3×105 m s-1, then the value of x is _____.: (Given mass of electron =9×10-31 kg, charge on electron =1.6×10-19 C.)

Correct answer: 14

Solution

Figure

Applying conservation of energy

-eVn+12mvi2=-eVp+12mvf2

We know, Vn-Vp=potential barrier=0.4 V

Then, we have, -eVn-Vp+12mvi2=12mvf2

⇒-1.6×10-19×0.4+12×9×10-31×36×1010=12×9×10-31 vf2

⇒-0.64×10-19+1.62×10-19=12×9×10-31vf2

⇒0.98×10-19=4.5×10-31vf2

⇒vf2=0.98×10124.5

⇒vf=0.466666×106

=4.6666×105 m s-1=143×105 m s-1

Hence, the correct answer is 14.

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