Q123 / 155 · WBJEE 2017 · Physics
A positive charge $Q$ is situated at the centre of a cube. The electric flux through any face of the cube is (in SI units)
- Correct answerA$\frac{Q}{6 \varepsilon_{0}}$
- B$4 \pi Q$
- C$\frac{Q}{4 \pi \varepsilon_{0}}$
- D$\frac{Q}{6 \pi \varepsilon_{0}}$
Solution
The positive charge $Q$ is situated at the centre of a cube
According to Gauss theorem, the flux from any closed surface
$$
\phi_{E}=\frac{Q}{\varepsilon_{0}}
$$
Cube has 6 faces, so electric flux from any face $\phi_{z}=\frac{Q}{6 \varepsilon_{0}}$
According to Gauss theorem, the flux from any closed surface
$$
\phi_{E}=\frac{Q}{\varepsilon_{0}}
$$
Cube has 6 faces, so electric flux from any face $\phi_{z}=\frac{Q}{6 \varepsilon_{0}}$Hence, the correct answer is option: 'A'.