Q170 / 180 · NEET 2026 (Re-NEET) · Zoology
A population of diploid organisms is at Hardy-Weinberg equilibrium. If the frequency of allele A is $0.1$, the frequency of AA is __________.
- A$0.99$
- Correct answerB$0.01$
- C$0.02$
- D$0.10$
Solution
According to the Hardy-Weinberg principle, the frequency of the homozygous genotype AA is given by $p^2$, where $p$ is the frequency of the allele A.
Given $p = 0.1$.
Frequency of AA $= p^2 = (0.1)^2 = 0.01$.
Answer: $0.01$
Given $p = 0.1$.
Frequency of AA $= p^2 = (0.1)^2 = 0.01$.
Answer: $0.01$
Hence, the correct answer is option: 'B'.