Q126 / 180 · KCET 2010 · Physics

A point object $O$ is placed in front of a glass rod having spherical end of radius of curvature $30 \mathrm{~cm}$. The image would be formed at
Figure

  • Correct answer
    A
    $30 \mathrm{~cm}$ left
  • B
    infinity
  • C
    $1 \mathrm{~cm}$ to the right
  • D
    $18 \mathrm{~cm}$ to the left

Solution

By using formula, $\frac{\mu_{2}}{\mathrm{v}}-\frac{\mu_{1}}{\mathrm{u}}=\frac{\mu_{2}-\mu_{1}}{\mathrm{R}}$ $\Rightarrow \quad \frac{1.5}{\mathrm{v}}-\frac{1}{(-15)}=\frac{(1.5-1)}{+30} \Rightarrow \mathrm{v}=-30 \mathrm{~cm}$ Negative sign shows that, image is obtained on the same side of object ie, towards left.

Hence, the correct answer is option: 'A'.

Relevant Questions