A plane wavefront is incident on a water surface at an angle of incidence $60^{\circ}$ then it gets refracted at $45^{\circ} .$ The ratio of width of incident wavefront to that of refracted wavefront will be $\left[\sin \frac{\pi}{4}=\cos \frac{\pi}{4}=\frac{1}{\sqrt{2}}, \sin 60^{\circ}=\frac{\sqrt{3}}{2}, \cos 60^{\circ}=\frac{1}{2}\right]$

• A

  $\frac{\sqrt{3}}{2}$
• B

  $2 \sqrt{3}$
• Correct answer
  C

  $\frac{1}{\sqrt{2}}$
• D

  $\sqrt{2}$

Hence, the correct answer is option: 'C'.