Q82 / 90 · JEE Main 2019 (10 Apr Shift 2) · Physics

A plane is inclined at an angle α=30° with respect to the horizontal. A particle is projected with a speed  u=2 m s-1 , from the base of the plane, making an angle θ=15° with respect to the plane as shown in the figure. The distance from the base, at which the particle hits the plane is close to:
(Take  g=10 m s-2 )
Figure

  • Correct answer
    A
    20 cm
  • B
    18 cm
  • C
    14 cm
  • D
    26 cm

Solution

Range =2u2sinαcos⁡α+θgcos2⁡θ
α=angle of inclination=30°
θ=angle of projection from inclination=15°
u=2 m/s
R=222sin15°cos⁡15°+30°gcos2⁡30°=8sin⁡15°cos45°g cos230°  sin15°=3-122
R=453-1 3≈0.2 m
R≈20 cm

Hence, the correct answer is option: 'A'.

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