Q61 / 75 · JEE Main 2020 (08 Jan Shift 2) · Physics

A plane electromagnetic wave of frequency 25GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic filed is given by B→=5×10-8 j^ T. The corresponding electric field E→ is (speed of light =3×108 m s-1 )

  • A
    1.66×10-16i^ Vm
  • B
    -1.66×10-16i^ Vm
  • C
    -15i^ Vm
  • Correct answer
    D
    15i^ Vm

Solution

Given, the electromagnetic wave is propagating in z i.e., +k^ direction.

The relation between the magnitudes of electric field, magnetic field and the speed of light is given by

EB=C

⇒ E=B×C
⇒ E=5×10-8×3×108=15 V m-1

We know that the direction of propagation of electromagnetic wave is along E→×B→.

So, E→=15 i^ V m-1

Hence, the correct answer is option: 'D'.

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