Q70 / 75 · JEE Main 2020 (09 Jan Shift 2) · Physics

A plane electromagnetic wave is propagating along the direction i^+j^2, with its polarization along the direction k.^ The correct form of the magnetic field of the wave would be (here B0 is an appropriate constant):

  • Correct answer
    A
    B0i^-j^2cosωt-ki^+j^2
  • B
    B0j^-i^2cosωt+ki^+j^2
  • C
    B0k^cosωt-ki^+j^2
  • D
    B0i^+j^2cosωt-ki^+j^2

Solution

 

Polarization of EM Wave means Direction of Its electric Field

Electric field vector is along k^

So, unit electric filed vector, E→=k^ (Given)

Direction of wave,c^=i^+j^2  (Given)

B^  denotes unit magnetic field vector.

B^=C^ ×E^

B^=i^+j^2×k^=i^-j^2

General Form is B=(B0B^)cosωt-c^k

where B0 is Magnitude of Magnetic Field

So, B=B0i^-j^2cosωt-ki^+j^2

Hence, the correct answer is option: 'A'.

Relevant Questions