Q19 / 90 · JEE Main 2013 (07 Apr) · Chemistry

A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 3 7 . 0 ∘ C. As it does so, it absorbs 208 J of heat. The values of q and w for the process will be 
(R = 8.314 J/mol K) (ln7.5 = 2.01)

  • A
    q = - 2 0 8 J , w = + 2 0 8 J
  • B
    q = + 2 0 8 J , w⁡ = + 2 0 8 J
  • Correct answer
    C
    q = + 2 0 8 J , w⁡ = - 2 0 8 J
  • D
    q = - 2 0 8 J , w⁡ = - 2 0 8 J

Solution

Since, temperature remains constant, the process will be isothermal by nature.
For Isothermal reversible expansion:
Δ E = 0 = q + w
q = - w
q = + 2 0 8  J       {heat absorbed so +ve}
w = - 2 0 8  J      {expansion so work done is -ve}

Hence, the correct answer is option: 'C'.

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