A pipe closed at one end has length 83 cm. The number of possible natural oscillations of air column whose frequencies lie below 1000 Hz are (velocity…

Question

A pipe closed at one end has length 83 cm. The number of possible natural oscillations of air column whose frequencies lie below 1000 Hz are (velocity of sound in air =332 m s^(-1))

MARKS Content Team · Accepted Answer

Correct answer: (C) 5. Fundamental frequency n=V/4L =332/(4×83×10^(−2))=100 . Hence possible frequencies are n=100 . n_1 =300. n_2 =500. n_3 =700. n_5 =900.

A pipe closed at one end has length $83 cm$ . The number of possible natural oscillations of air column whose frequencies lie below $1000 Hz$ are (velocity of sound in air $= 332 m s^{- 1}$ )

Solution

More Waves and Sound Questions

A pipe closed at one end has length 83 cm. The number of possible natural oscillations of air column whose frequencies lie below 1000 Hz are (velocity of sound in air =332 m s-1)

Solution

More Waves and Sound Questions

A pipe closed at one end has length $83 cm$ . The number of possible natural oscillations of air column whose frequencies lie below $1000 Hz$ are (velocity of sound in air $= 332 m s^{- 1}$ )