A person of mass $60 \mathrm{~kg}$ is inside a lift of mass $940 \mathrm{~kg}$ and presses the button on control panel. The lift starts moving upwards with an acceleration $1.0 \mathrm{~m} / \mathrm{s}^2$. If $g=10 \mathrm{~m} / \mathrm{s}^2$, the tension in the supporting cable is

• A

  $9680 \mathrm{~N}$
• Correct answer
  B

  $11000 \mathrm{~N}$
• C

  $1200 \mathrm{~N}$
• D

  $8600 \mathrm{~N}$

Solution

$$ \begin{aligned} & \text { Total mass }=\text { Mass of lift }+ \text { Mass of person } \\ & =940+60=1000 \mathrm{~kg} \\ & T-m g=m a \\ & \text { Hence, } T-1000 \times 10=1000 \times 1 \\ & T=11000 \mathrm{~N} \\ & \end{aligned} $$

Hence, the correct answer is option: 'B'.