A particular semiconductor in equilibrium has $1\times {10}^{16} {\mathrm{cm}}^{-3}$ donor atoms, $1.1 \times {10}^{17} {\mathrm{cm}}^{-3}$ acceptor atoms. If the intrinsic carrier density $\left(n_{\mathrm{i}}\right)$ of the semiconductor is ${10}^{12} {\mathrm{cm}}^{-3}$, then the electron density in it will be

• A

  ${10}^{16} {\mathrm{cm}}^{-3}$
• B

  ${10}^{12} {\mathrm{cm}}^{-3}$
• C

  $1.1\times {10}^{17} {\mathrm{cm}}^{-3}$
• Correct answer
  D

  ${10}^7 {\mathrm{cm}}^{-3}$

Hence, the correct answer is option: 'D'.