A particle undergoes a one-dimensional motion such that its velocity varies according to $v\left(x\right)\mathit{=}\beta x^{\mathit{-}2n}$, where $\beta$ and $\mathit{\text{n}}$ are constants and $x$ is the position of the particle. The acceleration of the particle as a function of $x$ is given by

• A

  $\mathit{-}2n{\beta }^2{x}^{\mathit{-}2n\mathit{-}1}$
• Correct answer
  B

  $-2n{\beta }^2{x}^{-4\mathrm{n}-1}$
• C

  $-2n{\beta }^2{x}^{-2\mathrm{n}+1}$
• D

  $-2n{\beta }^2{x}^{-4\mathrm{n}+1}$

Hence, the correct answer is option: 'B'.