Q98 / 150 · JEE Main 2006 · Physics
A particle of mass $100 \mathrm{~g}$ is thrown vertically upwards with a speed of $5 \mathrm{~m} / \mathrm{s}$. the work done by the force of gravity during the time the particle goes up is
- A$0.5 \mathrm{~J}$
- B$-0.5 \mathrm{~J}$
- Correct answerC$-1.25 \mathrm{~J}$
- D$1.25 \mathrm{~J}$
Solution
$-m g h=-m g\left(\frac{v^2}{2 g}\right)=-1.25 \mathrm{~J}$
Hence, the correct answer is option: 'C'.