A particle of mass $10 \mathrm{g}$ moves along a circle of radius $6.4 \mathrm{cm}$with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to $8\times {10}^{-4}\mathrm{ }\mathrm{J}$ by the end of the second revolution after the beginning of the motion?

• A

  $0.18\mathrm{\hspace{0.17em}}\mathrm{m}\mathrm{\hspace{0.17em}}{\mathrm{s}}^{-2}$
• B

  $0.2\mathrm{\hspace{0.17em}}\mathrm{m}\mathrm{\hspace{0.17em}}{\mathrm{s}}^{-2}$
• Correct answer
  C

  $0.1\mathrm{\hspace{0.17em}}\mathrm{m}\mathrm{\hspace{0.17em}}{\mathrm{s}}^{-2}$
• D

  $0.15\mathrm{\hspace{0.17em}}\mathrm{m}\mathrm{\hspace{0.17em}}{\mathrm{s}}^{-2}$

Hence, the correct answer is option: 'C'.