Q38 / 214 · NTA Abhyas (NEET) 2020 · Physics · Oscillations

A particle moves such that its acceleration is given by

a=-βx-2

Here : β is a positive constant and x is the position from origin. Time period of oscillations is

  • A
    2πβ
  • Correct answer
    B
    2π1β
  • C
    2πβ+2
  • D
    2π1β+2

Solution

a=-βx-2

as a=-ω2x-x0

by comparing

ω2=β

⇒T=2π1β

Hence, the correct answer is option: 'B'.

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