Q22 / 72 · NTA Abhyas (JEE Main) 2020 · Physics · Motion In Two Dimensions

A particle is projected towards the north with speed 20 ms at an angle 45o with horizontal. Ball gets horizontal acceleration of 7.5 ms2 towards east due to wind. Range of ball (in meter) minus 42 m will be

Correct answer: 8

Solution

Time of flight : T=2usin⁡θg=22 s
Range (along north) =u2sin⁡2θg=40 m
Range (along east) =12aT2=30 m
∴ Range =302+402=50 m

Hence, the correct answer is 8.

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