Q112 / 160 · JIPMER 2005 · Physics
A particle is kept at rest at the top of a sphere of diameter 42 m . When disturbed slightly, it slides down. At what height $h$ from the bottom, the particle will leave the sphere?
- A14 m
- B28 m
- Correct answerC35 m
- D7 m
Solution
The condition of slipping by particle from top is given by
$\cos \theta=2 / 3$
From the figure,
$h=r \cos \theta=21 \times \frac{2}{3}=14 \mathrm{~m}$
Therefore, the required height at which the particle will leave the sphere is
$=21+h=21+14=35 \mathrm{~m}$
$\cos \theta=2 / 3$
From the figure,
$h=r \cos \theta=21 \times \frac{2}{3}=14 \mathrm{~m}$
Therefore, the required height at which the particle will leave the sphere is
$=21+h=21+14=35 \mathrm{~m}$Hence, the correct answer is option: 'C'.