Q101 / 160 · JIPMER 2005 · Physics

A particle is executing the motion $x=a \cos (\omega t-\theta)$. The velocity of the particle is

  • A
    $a \omega \cos \theta$
  • Correct answer
    B
    $a \omega$
  • C
    $a \omega \sin \theta$
  • D
    None of the above

Solution

Given equation is $x=a \cos (\omega t-\theta)$ So, velocity $\left|\frac{d x}{d t}\right|=a \omega \sin (\omega t-\theta)$ At $(\omega t-\theta)=90^{\circ}, \quad$ the velocity will be maximum, therefore the maximum velocity is $v=a \omega$

Hence, the correct answer is option: 'B'.

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