Q35 / 214 · NTA Abhyas (NEET) 2020 · Physics · Oscillations

A particle executes SHM along a straight line so that its period is 12 s. The time it takes in traversing a distance equal to half its amplitude from its equilibrium position is-

  • A
    6 s
  • B
    4 s
  • C
    2 s
  • Correct answer
    D
    1 s

Solution

for T = 12 s, ω= 2π T = 2π 12 = π 6

Using x=Asin( ωt ) (from equilibrium position)

A 2 =Asin( π 6 t )

⇒ π 6 t=30°= π 6

⇒ t=1 s

Hence, the correct answer is option: 'D'.

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