Q128 / 180 · AIIMS 2018 (27 May) · Physics
A paramagnetic substance of susceptibility $3 \times 10^{-4}$ is placed in a magnetising field of $4 \times 10^{-4} \mathrm{~A} \mathrm{~m}^{-1}$. Then the intensity of magnetisation in the units of $\mathrm{A} \mathrm{m}^{-1}$ is
- A$1.33 \times 10^8$
- B$0.75 \times 10^{-8}$
- Correct answerC$12 \times 10^{-8}$
- D$14 \times 10^{-8}$
Solution
$\begin{aligned} I & =\chi H=\left(4 \times 10^{-4}\right) \times\left(3 \times 10^{-4}\right) \\ & =12 \times 10^{-8} \mathrm{~A} \mathrm{~m}^{-1}\end{aligned}$
Hence, the correct answer is option: 'C'.