Q64 / 75 · JEE Main 2020 (07 Jan Shift 1) · Physics

Figure
A parallel plate capacitor has plates of area A separated by distance d between them. It is filled with a dielectric which has a dielectric constant that varies as Kx=K01+αx where x is the distance measured from one of the plates. If αd<<1, the total capacitance of the system is best given by the expression:

  • Correct answer
    A
    AK0ε0d1+αd2
  • B
    AK0ε0d1+αd22
  • C
    AK0ε0d1+α2d22
  • D
    AK0ε0d1+αd

Solution

Capacitance of element, dC=K01+αxε0Adx
∫1dC=∫0ddxK0ε0A1+αx
⇒1C=1K0ε0Aαln1+αd
Given αd≪1
⇒1C=1K0ε0Aααd-α2d22
⇒1C=dK0ε0A1-αd2
⇒C=K0ε0Ad1+αd2

Hence, the correct answer is option: 'A'.

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