Q46 / 120 · JEE Main 2007 · Mathematics
A pair of fair dice is thrown independently three times. The probability of getting a score of exactly $9$ twice is
- A$1 / 729$
- B$8 / 9$
- C$8 / 729$
- Correct answerD$8 / 243$
Solution
Probability of getting score $9$ in a single throw $=\frac{4}{36}=\frac{1}{9}$
Probability of getting score $9$ exactly twice $={ }^3 \mathrm{C}_2 \times\left(\frac{1}{9}\right)^2 \times \frac{8}{9}=\frac{8}{243}$.
Hence, the correct answer is option: 'D'.