Q158 / 160 · AP EAMCET 2023 (15 May Shift 1) · Physics
A p-n junction diode is reverse biased with a voltage of $8 \mathrm{~V}$. If the resistance of the diode is $4 \times 10^7 \Omega$, then the reverse saturation current is
- A$32 \mu \mathrm{A}$
- B$2 \mu \mathrm{A}$
- Correct answerC$0.2 \mu \mathrm{A}$
- D$0.5 \mu \mathrm{A}$
Solution
Saturation current
$$
\begin{aligned}
& \mathrm{I}=\frac{\mathrm{v}(\text { reverse biased voltage })}{\text { diode resistance }} \\
& =\frac{8}{4 \times 10^7}=0.2 \mu \mathrm{A}
\end{aligned}
$$
Hence, the correct answer is option: 'C'.