Q70 / 90 · JEE Main 2010 · Physics

A nucleus of mass $M+\Delta m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $\mathrm{c}$. 40. The binding energy per nucleon for the parent nucleus is $E_1$ and that for the daughter nuclei is $E_2$. Then

  • A
    $\mathrm{E}_2=2 \mathrm{E}_1$
  • B
    $E_1>E_2$
  • Correct answer
    C
    $E_2>E_1$
  • D
    $\mathrm{E}_1=2 \mathrm{E}_2$

Solution

After decay, the daughter nuclei will be more stable hence binding energy per nucleon will be more than that of their parent nucleus.

Hence, the correct answer is option: 'C'.

Relevant Questions