A nucleus of lead $\mathrm{Pb}_{82}^{214}$ emits two electrons followed by an alpha particle. The resulting nucleus will have

• Correct answer
  A

  82 protons and 128 neutrons
• B

  80 protons and 130 neutrons
• C

  82 protons and 130 neutrons
• D

  78 protons and 134 neutrons

Solution

$82 \rightarrow$ Proton $210-82=128$ Neutron

Hence, the correct answer is option: 'A'.