$\left(\text{A}\right)\stackrel{{\text{NH}}_{\text{3}}}{\to }\left(\text{B}\right)\stackrel{{\text{KOH/Br}}_{\text{2}}}{\to }{\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}{\text{CHNH}}_{\text{2}}$
$\mathrm{A}$ is

• A

  
• B

  
• Correct answer
  C

  
• D

  

Solution

In Hoffman degradation reaction one carbon decreases

Hence, the correct answer is option: 'C'.