Q120 / 155 · WBJEE 2022 · Physics

A neutral conducting solid sphere of radius $\mathrm{R}$ has two spherical cavities of radius a and $b$ as shown in the figure. Centre to centre distance between two cavities is $c . q_a$ and $q_b$ charges are placed at the centres of cavities respectively. The force between $q_a$ and $q_b$ is

A neutral conducting solid sphere of radius $\mathrm{R}$ has two spherical cavities of radius a and $b$ as shown in the figure. Centre to centre distance between two cavities is $c . q_a$ and $q_b$ charges are placed at the centres of cavities respectively. The force between $q_a$ and $q_b$ is
- Correct answerA$\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}_{\mathrm{a}} \mathrm{q}_{\mathrm{b}}}{\mathrm{c}^2}$
- B$\frac{1}{4 \pi \varepsilon_0} q_a q_b\left(\frac{1}{a^2}+\frac{1}{b^2}\right)$
- Czero
- Dinsufficient data
Solution
Considering only interaction between charge $q_a$ and $q_b$.
Hence, the correct answer is option: 'A'.