Q194 / 225 · JEE Main 2005 · Physics

A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 volt, the resistance in ohms needed to be connected in series with the coil will be

  • A
    $10^3$
  • B
    $10^5$
  • C
    99995
  • Correct answer
    D
    9995

Solution

$I_g=15 \mathrm{~mA} \quad V g=75 \mathrm{mV}$ $\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}_g}-\frac{\mathrm{V}_g}{I_g}$

Hence, the correct answer is option: 'D'.

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